X^2+12=17x

Solution for X^2+12=17x equation:

X^2+12=17X

We move all terms to the left:

X^2+12-(17X)=0

a = 1; b = -17; c = +12;
Δ = b2-4ac
Δ = -172-4·1·12
Δ = 241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-\sqrt{241}}{2*1}=\frac{17-\sqrt{241}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+\sqrt{241}}{2*1}=\frac{17+\sqrt{241}}{2}
$